y=-16y^2=268

Solution for y=-16y^2=268 equation:

y=-16y^2=268

We move all terms to the left:

y-(-16y^2)=0

We get rid of parentheses

16y^2+y=0

a = 16; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·16·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*16}=\frac{-2}{32}
=-1/16
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*16}=\frac{0}{32}
=0
$